In a right angle triangle ABC with right angle at B, in which a = 24 units, b = 25 units and angle BAC = theta. then, find cos theta and tan theta
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As Right ∆ABC, with Right Angle at B...
A
|\
| \
|. \
B. C
AB=24 ut. BC=25ut
Angle BAC=∅
:- by Pythagoras Theorem:
p²+b²=h²
24²+25²=h²
then solve it and you will get the value of h or AC.
After that find cos∅=b/h or BC/AC
and tan∅=p/b or AB/BC
A
|\
| \
|. \
B. C
AB=24 ut. BC=25ut
Angle BAC=∅
:- by Pythagoras Theorem:
p²+b²=h²
24²+25²=h²
then solve it and you will get the value of h or AC.
After that find cos∅=b/h or BC/AC
and tan∅=p/b or AB/BC
Answered by
48
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