in a right angle triangle ABC with right angle at B. in which a=24 units,b=25units and angle BAC =©
then find cos©and tan©..
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small a is equal to opposite side of angle a
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Answer:
by Pythagoras theorem
AB^2+ BC^2=AC^2
c^2+24^2=25^2
c^2+567=625
c^2=625-567=58
c=√58
In triangle ABC angle A=©
cos©= adjacent side/= AB/
opposite side BC
= √58/
24
tan©= opposite side/= BC/
adjacent side AB
=24/
√58
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