Question

in a right angle triangle base equal to 3 cm perpendicular equal 4 centimetre hypotenuse be​

Answer 1

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• QuestioN :

$\sf \mapsto \: base = 3$

$\sf \mapsto perpendicular \: = 4$

$\sf \mapsto \: hypotenuse \: = {?}$

• SolutioN :

$\sf \: we \: \: know,$

$\mapsto \sf\: The \: \: Pythagoras \: \: Theorem : \\ \\ \underline{\sf \: {base}^{2} + { perpendicular}^{2} = {hypotenuse}^{2} }$

Using Pythagoras Theorem,

$\: \: \: \sf \: \sqrt{{3}^{2} + {4}^{2} }$

$\sf \: = 5 \: \: cm$

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