Question

In a right Angle triangle hypotenus is 5cm and ratio of other two sides 1:2 find the sides


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Answer 1

Let base = 1x

Perpendicular = 2x

Using Pythagoras' Theorem

(Hypotenuse)² = (Base)² + (Perpendicular)²

5² = x² + (2x)²

25 = x² + 4x²

25 = 5x²

25/5 = x²

x² = 5

x = √5

x = 2.236

Base = 2.236 cm

Perpendicular = 2 × 2.236 = 4.472 cm

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Answer 2

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$Given: \: \:  △ABC \: \:  is \: \: a \: \: right \: \: angled \: \: triangle.$

$Hypotenuse AC=5cm$

$and AB:BC=1:2$

$⇒ AB=1x,BC=2x$

$In \: \: right \: \: angled △ABC,$

$By \: \: pythagoras \: \: theorem$

$AC²=AB²+BC²$

$⇒5²=(1x)²+(2x)²$

$⇒25=x²+4x²$

$⇒25=5x²$

$⇒x=5$

$Hence, AB=1x=1×√5=√5cm$

$BC=2x=2×√5=25cm$