Question

In a right angle triangle hypotenuse is 20 and the other two side are in the ratio 4:3.find the other two side

Answer 1

Let the ratio be x
b = 4x
h = 3x

Using pythagoras theorem
(H)^2 = (b)^2 + (p)^2
(20)^2 = (4x)^2 + (3x)^2
400 = 25x^2
16 = x^2
4 = x

b = 16
h = 12

Answer 2

Given hypotenuse, h = 20 cm

Ratio of other two sides, a:b = 4:3

Let altitude of the triangle be 4x and base be 3x.

According to Pythagoras theorem,

h2 = b2+a2

202 = (3x)2+(4x)2

400 = 9x2+16x2

25x2 = 400

x2 = 400/25

x2 = 16

Taking square root on both sides

x = 4

so base, b = 3x = 3×4 = 12

altitude, a = 4x = 4×4 = 16

Hence the other sides are 12 cm and 16 cm.