In a right angle triangle OAB,A=90,OA=24m and AB=10m.Find the sum of digits of length OB
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Step-by-step explanation:
for finding OB
use Pythagoras theorem
OBsq=OA+AB
OBsq equal to 24sq + 10sq
OBsq is equal to 576+100 =676
OB is equal to 26
Sum of OB digits is equal to 2+6=8
got it!!!
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