Question

In a right angle triangle, one of the sides exceeds the other by 20°. Find the measure of both the acute angles in the right angled triangle.

Answer 1

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GIVEN :

=> A RIGHT ANGLED TRIANGLE IS GIVEN :

=> ONE ANGLE IS OF 90°

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=> SECOND ANGLE EXCEEDS BY 20° THAN THIRD ONE .....

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TO FIND :

=> THE MEASURES OF ALL THE ANGLES

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LET,

=> ONE SIDE OF THE TRIANGLE IS X

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SECOND SIDE WILL BE :

=> ( X + 20 ) °

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=> SUM OF MEASURES OF ALL ANGLES OF A TRIANGLE IS 180°

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=> X° + ( X + 20 ) ° + 90° = 180°

=> X° + X° + 20 ° = 180° - 90 °

=> 2X = 180° - 90° - 20°

=> 2X° = 70°

=> X° = ( 70 / 2 )°

=> X = 35°

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THIRD SIDE :

=> ( X + 20 ) °

=> ( 35 + 20 ) °

=> 55°

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=> FIRST SIDE = 90°

=> SECOND SIDE = 35°

=> THIRD SIDE = 55°

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HOPE IT WILL HELP U.....

THANKS AGAIN ......

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Answer 2

Answer:

Step-by-step explanation:

Let the angle of X

Angle first =X

Second angle =X+20

Sum of triangle=180

X+X+20=180

2x+20=180

2x=180-20

2x=160

X=160/2

X=80

First angle is 80

Second angle is