in a right angle triangle, one of the two angle is 4times the other angle. find the angle of the triangle
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in right angle one angle measure 90° which is in the opposite side of hypotenuse
let the angle be x
ATQ
90+x+4x = 180
90+5x = 180
5x = 180-90=90
x = 90/5=18
one angle measure 18°
other angle measure 4x=4×18=72°
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