Question

in a right angle triangle one side is 126 m and difference hypotenuse and other side is 42 m find the length of both side and area of the triangle​

Answer 1

Answer:

S1= 126m

hypotenuse= S2 = 42cm= 0.42m

let the S2 be X

hypotenuse= X = 0.42m

Answer 2

Solution:-

given:-

1) in a right angle triangle one side

is 126 m.

2) difference hypotenuse and other

side is 42 m.

find ;- the length of both side and area of the triangle.

(1st side) = 126m

hypotenuse - ( 2cd side) = 42cm = 0.42m

Let the 2cd side be x.

=> hypotenuse - x = 0.42

=> hypotenuse = 0.42 + x

By Pythagoras theorem.

=> 17.64 + 0.84x = 126

=> 0.84x = 126 - 17.64

=> 0.84x = 108.36

=> x = 108.36/0.84

=> x = 129

so

=> ( 2cd side) = 129m

=> hypotenuse = x + 0.42

=> hypotenuse = 129 + 0.42

=> hypotenuse = 129.42m

=> Area of right angled triangle

=1/2 × product of perpendicular sides

=1/2 × 126 × 129

= 63 × 129

= 8127 metre sq.

Therefore,

The area of right angled triangle is 8127sq.m with 129 and 126 are length & breadth respectively.

i hope it helps you..