Question

In a right angle triangle PQR, right angled at Q, PQ = 4 cm, QR = 5 cm. Find PR.

Answer 1

$\huge\green {\underline {\mathfrak {Answer:}}}$

$\underline {\bold{\pink{Given:}}}$

➣$\triangle PQR\ is\ right -angled$

➣$PQ = 4\ cm$

➣$QR = 5 \ cm$

$\underline {\bold{\pink {Find:}}}$

➣$PR$

$\underline {\bold {\pink{Solution:}}}$

✦$\color{red}{\boxed{\boxed{\color{blue}{By \ pythagoras \ theorem :}}}}$

$\boxed{Hypotenuse^2 = Base^2 + Perpendicular^2}$

$\therefore PR^2 = PQ^2 +QR^2$

$\implies PR^2 = 4^2 + 5^2$

$\implies PR^2 = 16 + 25$

$\implies PR^2 = 41$

$\color{cyan}{\boxed{\implies{\boxed{\color{red}{PR = \sqrt{41}}}}}}$

Answer 2

Answer:

41

Step-by-step explanation:

a² + b² = c²

a²= 4²=16

b²=5²=25

a²+b²= 16+25

= 41

= √41

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