In a right angle triangle PQR, right angled at R if tan Q =12/5 and RQ=75 find PQ and sinP
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Answer:
Correct option is
A
5
pythagorouis theorem
PR
2
=PQ
2
+QR
2
PR
2
=5
2
+10
2
PR
2
=
125
PR
2
=5
5
sinP=
PR
QR
sinP=
QR
PR
sinP=
5
5
10
sin
2
P=
125
100
=
5
4
=
m
4
m=5
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