in a right angle triangle the difference between areas of square drawn on perpendicular sides of a triangle is 7 Sq. cm. and the areas of square drawn on hypotenuse is 25 Sq. cm. find sides of triangle
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Correct Question :- In a right angle triangle, the areas of square drawn on perpendicular sides of a triangle is 49 Sq. cm. and the areas of square drawn on hypotenuse is 625 Sq. cm. find the sides of the triangle ?
Solution :-
we know that,
- side of square = √(Area)
so,
→ Area of square drawn on perpendicular side = 49 cm²
→ Perpendicular side = √(49) = 7 cm.
similarly,
→ Area of square drawn on hypotenuse side = 625 cm²
→ Perpendicular side = √625 = 25 cm.
then,
→ Base = √[(Hypotenuse)² - (Perpendicular)²]
→ Base = √[(25)² - (7)²]
→ Base = √(625 - 49)
→ Base = √576
→ Base = 24 cm.
therefore, the sides of the triangle are 7 cm , 24 cm and 25 cm.
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