In a right angle triangle ,the hypotenuse is 10 cm more than the shortest side. If third side is 6 CM less than the hypotenuse, find the sides of the right angle triangle
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Use the phythagores therom
Hyp squre =adj squre +opp squre
syedHamed515:
x (x-10)+2 (x-10)
(x-10) (x+2)
x = 10 ; x=-2
as Hyp can't be negative so x = 10
now put the value of x in 2x + 6
2(10)+6
20 + 6 = 26
Hence,we got the answer
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Answer:
16.95
26.95
20.95
Step-by-step explanation:
Let the shortest side be x then the sides are as follows :
Hypotenuse = (x + 10) cm
The third side = (x + 10 - 6) cm = x + 4
We will use Pythagoras theorem to relate the three sides.
Given the sides of a right angled triangle a, b and c :
a² + b² = c²
Applying this to our sides above we have :
x² + (x + 4)² = (x + 10)²
Expanding the equation we have :
x² + x² + 8x + 16 = x² + 20x + 100
Collecting the like terms together we have :
2x² - x² + 8x - 20x + 16 - 100 = 0
x² - 12x - 84 = 0
We will use the quadratic formula :
[12 +/- (12² + 4 × 1 × 84)^½] /2
x = 16.95
Hypotenuse = 16.95 + 10 = 26.95 cm
The third side = 16.95 + 4 = 20.95 cm
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