Question

In a right angle triangle the hypotenuse is 10 CM more than the shorter side. if the third side is 6 CM less than the hypotenuse, find the sides of the right angle triangle.

Answer 1

Let the shorter side be x

then the hypotenuse = (x + 10)

nd 3rd side = (x + 4)

now,

by Pythagoras theorem

$({x + 10}^{2}) = ({x}^{2}) + ({x + 4}^{2} )$

$= > ( {x}^{2} ) - 12x - 84 = 0$

we will get,

$x = 6 + 2 \sqrt{30} .....x = 6 - 2 \sqrt{30}$

we got ,

the shorter side

$(6 + 2 \sqrt{30} )cm$

hypotenuse

$(16 + 2 \sqrt{30} )cm$

nd 3rd side

$(10 + 2 \sqrt{30} )cm$

over...

Answer 2

Answer:

answer is right

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