Question

In a right angle triangle the length of
9 cm s 12cm respectively what is the length
of hypotenuse​

Answer 1

Answer:

15cm

Step-by-step explanation:

by pythagoras theorem

$x { }^{2} = 12 {}^{2} + 9 {}^{2}$

${x}^{2} = 144 + 81$

$x {}^{2} = 225$

by taking squareroot to bothside

x=15

length of hypotenuse is 15cm

Answer 2

$\large\star\boxed{\bf{\underline{\underline{\green{GIVEN:-}}}}}$

Side (s) = 12 cm

Base (b) = 9 cm

$\large\</strong><strong>star\boxed</strong><strong>{\</strong><strong>b</strong><strong>f{\underline{\underline{\green{To\:find:-}}}}}$

hypotenuse (hypo) = ?

$\large\star\boxed{\bf{\underline{\underline{\green{SOLUTION:-}}}}}$

We know the pythagoras theorem.

According to the Pythagoras theorem,

${(hypo)}^{2} = {(s)}^{2} + {(b)}^{2}$

INSERTING THE VALUES,

$= > {(hypo)}^{2} = {(12)}^{2} + {(9)}^{2}$

$= > {(hypo)}^{2} = 144 + 81$

$= > {(hypo)}^{2} = 225$

$now \: as \: hypotenuse \: is \: in \: square \: we \: have \: </strong><strong>to</strong><strong> \: find \: its \: sq</strong><strong>u</strong><strong>a</strong><strong>re \: root$

SO BY SQUARE ROOTING BOTH SIDES,

$= > hypo = \sqrt{225}$

$we \: know \: that \: 15 \times 15 = 225 \: so \\ = > hypo = 15 \: cm$

SO THE LENGTH OF HYPOTENUSE IS 15 CM.