in a right angle triangle the measure of the other than the right angles are x+ 35 degree and x+ 5 find the measure of the two angle
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x + 35 +x + 5 + 90 = 180. ( asp)
2x + 40 = 180 - 90
2x + 40 = 90
2x = 90 - 40
x = 50/2
x = 25
1st angle = x + 35 = 25 + 35 = 60
2nd angle = x + 5 = 25 + 5 = 30
2x + 40 = 180 - 90
2x + 40 = 90
2x = 90 - 40
x = 50/2
x = 25
1st angle = x + 35 = 25 + 35 = 60
2nd angle = x + 5 = 25 + 5 = 30
Answered by
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hi friend!
GIVEN: Angle A = 130°
TO FIND : Angle DPE = Angle CPB =?
Let angle B be 2x
So, angle C = 180 - (130 +2x) = 50–2x
So angle DCB =(50–2X)/2
Now, angle CDA = 2x + (50–2x)/2 ( as exterior angle = the sum of 2 opposite interior angles)
=> angle CDA = (2x +50)/2 = x+ 25 ……..(1)
Now,in triangle AEB, angle AEB =180 - (130+x) = 50 -x ………….(2)
So, in quadrilateral ADPE,
angle DPE = 360 -(130 + x+25 + 50-x)
=> angle DPE = 360- 205
=> angle DPE = 155°
hope my answer helps you
keep smiling
GIVEN: Angle A = 130°
TO FIND : Angle DPE = Angle CPB =?
Let angle B be 2x
So, angle C = 180 - (130 +2x) = 50–2x
So angle DCB =(50–2X)/2
Now, angle CDA = 2x + (50–2x)/2 ( as exterior angle = the sum of 2 opposite interior angles)
=> angle CDA = (2x +50)/2 = x+ 25 ……..(1)
Now,in triangle AEB, angle AEB =180 - (130+x) = 50 -x ………….(2)
So, in quadrilateral ADPE,
angle DPE = 360 -(130 + x+25 + 50-x)
=> angle DPE = 360- 205
=> angle DPE = 155°
hope my answer helps you
keep smiling
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