In a right angle triangle xyz side x<y<z if 2x +7z =9y and x = 12. Find the value of sec y - sec x
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x + y + z = 4 + 1 + 2 = 7 [Ans]
Step-by-step explanation:
According to the question in order to find the values of x y z we must know what are the factors of 2352.
The factors of 2352 are:
2352 = (2*2*2*2)*(3*1)*(7*7). = 2^{4}2
Comparing it with 2352 = 2^{x} * 3^{y} * 7^{z}
∴Therefore the sum of x,y and z will be (4+1+2) equals to 7.
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