Question

in a right angle tringle abc ,b=90 degree,if ab=12 bc=16 find ac=_____​

Answer 1

AC=20 mark me as brainiest plz.

(AC)2=(AB)2+(BC)2

(AC)2= (12)2+(16)2

(AC)2=400

AC=√400

AC=20..

Answer 2

Answer:

Given ΔABC is a right-angled triangle.

Also given,

      $AB = 12$

      $BC = 16$

We know that,

$AC^2=AB^2+BC^2$  $(Pythagoras$ $theorem)$

∴ $AC^2= 12^2+16^2$

          $=144+ 256$

          $= 400$

  $AC^2 = 400$

          $=\sqrt{400}$

∴ $AC = 20$

               Hope it helps you ^_^