Math, asked by paidiranganadham76, 4 months ago

In a right angled A ABC, ZA is acute, ZB= 90° and tan A =
12
i) cos A
From the adjoining fi
ii) cosecA - cotA​

Answers

Answered by abibala194
0

Answer:

1) △ABC is a right angled triangle and right angle at B

sinA=

AC

BC

, cosA=

AC

AB

⟹sinA+cosA=

AC

BC

+

AC

AC =

AC

BC+AB

[We know that sum of two sides of a triangle is greater than the third side]

⟹sinA+cosA>

AC

AC

=1

Hence, sinA+cosA>1

2) Left hand sideLeft hand side

=(cscA−cotA)2=(1sinA−cosAsinA)2=(cscA−cotA)2=(1sinA−cosAsinA)2

=(1−cosA)2(sinA)2=(1−cosA)2(sinA)2

=(1−cosA)21−cos2A=(1−cosA)21−cos2A

=(1−cosA)2(1−cosA)(1+cosA)=(1−cosA)2(1−cosA)(1+cosA)

=(1−cosA)(1+cosA)=(1−cosA)(1+cosA)

=Right hand side=Right hand side

Step-by-step explanation:

PLS make my answer brilliant

Answered by pranabandhubiswal
0

Answer:

cotA this is the hhi just joking

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