In a right angled A ABC, ZA is acute, ZB= 90° and tan A =
12
i) cos A
From the adjoining fi
ii) cosecA - cotA
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Answer:
1) △ABC is a right angled triangle and right angle at B
sinA=
AC
BC
, cosA=
AC
AB
⟹sinA+cosA=
AC
BC
+
AC
AC =
AC
BC+AB
[We know that sum of two sides of a triangle is greater than the third side]
⟹sinA+cosA>
AC
AC
=1
Hence, sinA+cosA>1
2) Left hand sideLeft hand side
=(cscA−cotA)2=(1sinA−cosAsinA)2=(cscA−cotA)2=(1sinA−cosAsinA)2
=(1−cosA)2(sinA)2=(1−cosA)2(sinA)2
=(1−cosA)21−cos2A=(1−cosA)21−cos2A
=(1−cosA)2(1−cosA)(1+cosA)=(1−cosA)2(1−cosA)(1+cosA)
=(1−cosA)(1+cosA)=(1−cosA)(1+cosA)
=Right hand side=Right hand side
Step-by-step explanation:
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Answer:
cotA this is the hhi just joking
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