In a right angled ABC, AB is a perpendicular to BC and angle C =50 Find the third angle
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Answered by
1
In triangle ABC
<A+<B+<C=180°
<A+90°+50°=180°
<A=180°-140°
<A=40°
<A+<B+<C=180°
<A+90°+50°=180°
<A=180°-140°
<A=40°
Answered by
3
as AB PERPENDICULAR TO BC
THEREFORE
angle ABC=90
AND angle ACB=50 as said
so
angle CAB=180-(90+50)
180-140
40
ANS
THEREFORE
angle ABC=90
AND angle ACB=50 as said
so
angle CAB=180-(90+50)
180-140
40
ANS
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