Question

in a right angled ABC ac=26m bc=10m find the length ofab

Answer 1

$26 {}^{2} - 10 {}^{2} = 676 - 100 \\ = 576 \\ \sqrt{576 } = 24cm$

Answer 2

according to phytagoras theroem
AC²=AB²+BC²
AB²=26²-10²
=676-100
=576
=√576
=24cm
hope it help