Question

in a right angled ∆ABC , right angled at A, if AD perpendicular BC such that AD = p, BC = a and AB = c then


1..p^2=b^2+c^2
2...1/p^2=1/b^2+1/c^2
3....p/a=p/b
4.....p^2=b^2 c^2
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Answer 1

Answer:

1..p^2=b^2+c^2 is the answer