In a right angled ABC, right angled at c,if AB=26cm BC=10cm find the value of AC
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ABC is right angle triangle therefore
by Pythagoras theorem:-
AB²+BC²=AC²
ΑΒ²=AC²−BC²
ΑΒ²=(26)²−(10)²
ΑΒ²=(26–10)(26+10)
AB²=16*36
AB=√16×36
ΑΒ=4×6
ΑΒ=24cm
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