Question

In a right angled ∆ ABC , Seg BC =90°, Seg AC=60°.In a right angled ∆PQR, Seg PQ=90°, Seg PR =60°. In a right angled ∆XYZ, Seg YZ = 90° , Seg XZ = 60°. Write Sin60° , Cos60° and Tan60° for ∆ in trigonometric ratios


Guys could plzzz answer.....​

Answer 1

Answer:

• sin60 = $\frac{\sqrt{3}}{2}$

• cos60=$\frac{1}{2}$
• Tan60=$\sqrt{3}$

Step-by-step explanation:

• tan60=sin60/cos60
• thank u