Question

in a right angled at b a c minus ab is equal to 2 cm BC is equal to 8 cm find the value of AC ​

Answer 1

Answer:

AC-AB=2

AB= AC-2 ----equation 1

BC=8cm(given)

Since ABC is right angled,

AC^2= AB^2+ BC^2(pythogoras theorem)

AC^2- AB^2=BC^2

(AC-AB)(AC+AB)= BC^2 (a^2-b^2=(a+b) (a-b) )

(2)( AC+AC-2) = 8

2AC-2= 8÷2

2AC= 4+2

AC=6÷2

AC=3cm

Answer 2

Answer:

thanks !!!

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