In a right angled at
B,
AC- AB = 2cm, BC=8cm
find the value of AC
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Step-by-step explanation:
AC-AB=2
AC=2+AB
now using pythogerous theorem
AC^2=AB^2+BC^2
(2+AB)^2=AB^2+BC^2
4+AB^2+4AB= AB^2+BC^2
4+4AB=8^2
4+4AB= 64
4AB=60
AB= 15
AC=2+AB
AC=2+15
AC=17
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