In a right angled isosceles triangle. If it's sides are increased by 75%, then the percentage change in its area is
option is given below:
1) 306.25%
2) 103.125%
3) 206.25%
4) 105.125%
shweta36:
have you participate in ANTHE
Answers
Answered by
4
Let h,a and a be the sides of right angled isosceles triangle.
then area (A1)= (1/2)*a*a
Now, all the sides are increased by 75%
Therefore, the new sides are 1.75h, 1.75a and 1.75a respectively.
The new area(A2) = (1/2)*(1.75a)(1.75a) = [(1/2)*a*a]
= 3.0625*(A1)
Therefore new area A2 is 3.0625 times of original area A1
% change = [(A2 - A1)/A1]*100 = 206.25%
Please note that % change is 206.25% (A1 + 2.0625A1) and % increase is 3.0625 times (A2 = 3.0625*A1)
Answer is 206.25%
then area (A1)= (1/2)*a*a
Now, all the sides are increased by 75%
Therefore, the new sides are 1.75h, 1.75a and 1.75a respectively.
The new area(A2) = (1/2)*(1.75a)(1.75a) = [(1/2)*a*a]
= 3.0625*(A1)
Therefore new area A2 is 3.0625 times of original area A1
% change = [(A2 - A1)/A1]*100 = 206.25%
Please note that % change is 206.25% (A1 + 2.0625A1) and % increase is 3.0625 times (A2 = 3.0625*A1)
Answer is 206.25%
Similar questions
Math,
7 months ago
English,
7 months ago
CBSE BOARD X,
7 months ago
Social Sciences,
1 year ago
Math,
1 year ago