Question

In a right angled ∆PQR, two of its sides PO and OR are equal. Find all angles of ∆PQR.
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Answer 1

Answer:

R.E.F image

In △ PQR using pythagoras theorem

(PR)

2

=(PQ)

2

+(QR)

2

625-49=(QR)

2

(QR)

2

=576

QR=24CM

now tan P =

7

24

and tan R =

24

7

tanP-tanR=

7

24

−

24

7

=

168

576−49

=

168

527

Answer 2

Step-by-step explanation:

In triangle POR

PQ = OR

Angle PQR = 90

Let the angle QPR be x

Angle QPR = Angle QPR ( Angle opposite of equal sides are equal)

Now,

x+x+90 = 180 ( Angle sum property)

2x = 90

x = 45