In a right angled triangle A LMN, M-90°. If/ (LM) = 12cm and / (LN) = 20cm, Find the length of seg MN
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Answered by
6
Answer:
16
Step-by-step explanation:
given,
LM= 12 cm
LN = 20 cm
by PGT
(LN)^2 = (LM)^2+ (MN)^2
(20)^2= (12)^2+ (mn)^2
400= 144+ MN^2
400-144= (MN)^2
256= MN^2
16= MN
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