Question

In a right angled triangle AB =3 unit,BC=4unit, then AC equal to

Answer 1

By Pythagoras theorem
${ab}^{2} + {bc }^{2} = {ac}^{2} \\ {3}^{2} + {4}^{2} = {ac}^{2} \\ 9 + 16 = {ac}^{2} \\ ac = \sqrt{25} \\ ac = 5cm$

Answer 2

In a right angled triangle AB = 3unit BC= 4unit, then AC equal to 5 unit