In a right angled triangle ABC, A = 90° and AB=AC, then find ZB and 2C.
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Step-by-step explanation:
Given,
∠A = 90° and AB = AC
A/q,
AB = AC
⇒ ∠ZB = ∠2C (Angles opposite to the equal sides are equal.)
Now,
∠A + ∠ZB + ∠2C = 180° (Sum of the interior angles of the triangle.)
⇒ 90° + 2∠ZB = 180°
⇒ 2∠ZB = 90°
⇒ ∠ZB = 45°
Thus, ∠ZB = ∠2C = 45°
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