Math, asked by prachi110606, 1 month ago

in a right angled triangle ABC AB =1 AC = √2 and BC = 1 find
Sin A
Cos C
Tan A
Cot A x Sec C ​

Answers

Answered by bcsharma1945
3

Answer:

sin A = 1/ root 2

cos C = 1/ root 2

tan A = 1

cot A × sec C = root 2

Step-by-step explanation:

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