Math, asked by msingh577, 6 months ago

In a right-angled triangle ABC, AB = X/2, BC = x+2 and AC = x+3. Find the value of x​

Answers

Answered by senoratalukdar
1

Answer:

AB=x/2. BC=x+2. CA=x+3 then x/2+(x+2)+x+3=180 x+2x+4+2x+6=360 ... It is a right angled triangle ... Find the ratios of 400ml to 1.8l · What is the value of x+y if 7x+y.

Step-by-step explanation:

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Answered by sambhavi875
3

Answer:

We are given, m∠B=90

o

AB=(x−3) cm

BC=(x+4) cm

AC=(x+6) cm

x=?

From pythagoras theorem,

AC

2

=AB

2

+BC

2

(x+6)

2

=(x−3)

2

+(x+4)

2

∴ x

2

+12x+36=x

2

−6x+9+x

2

+8x+16

∴ x

2

+12x+36=2x

2

+2x+25

∴ 2x

2

−x

2

+2x−12x+25−36=0

∴ x

2

−10x−11=0

∴ x

2

−11x+x−11=0

∴ x(x−11)+1(x−11)=0

∴ (x+1)(x−11)=0

So, x+1=0 or x−11=0

x=−1

or

x=11

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