In a right angled triangle ABC AC is the hypotenuse and the other two sides are of the lengths 12M and 9m. X is a point outside the triangle such that XA =36 and angle XAC=90 degree . Find XC by
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by Pythagoras theorem
12²+9²=AC²
144+81=AC²
AC=√225
AC=15
similarly
36²+15²=XC²
XC =√1521
XC =39
12²+9²=AC²
144+81=AC²
AC=√225
AC=15
similarly
36²+15²=XC²
XC =√1521
XC =39
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