Math, asked by Sinhaharsh, 5 months ago

In a right angled triangle ABC, angle A is right angle and AC = 5, AB = 3, BC = 4 units,

then find the value of sinB, cosB and tanC.​

Answers

Answered by Ssrinivas
0

Answer:

 \sin(b)  =  \frac{opp}{hyp}  =  \frac{5}{4}  \\  \cos(b) =  \frac{adj}{hyp}  =  \frac{3}{5}  \\  \tan(c)  =  \frac{opp}{adj}  =  \frac{5}{3}

Answered by dsah9628
1

Step-by-step explanation:

Here,

In a right angled triangle ABC, angle A is right angle and AC = 5, AB = 3, BC = 4 units.

Then,

sinB = AC/BC = 5/4

cosB= AB/BC = 3/4

And, tanC = AB/AC = 3/5

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