Question

In a right angled triangle ABC,Angle B=90.if the longest side is 3cm more than the middle side and the middle side is 3cm more than the shortedt one then find the sides of the triangle

Answer 1

in triangle ABC
let BC = x
AB = x-3
AC= x+3

now from figure
by pathagorus triplet
(AB) square + (BC) square = (AC) square
x sq + (x-3)sq = (3+x)sq. (by using identity (a+b)sq = a sq + b sq + 2ab
x sq + x sq - 6x +9 = 9 + 6x +x sq
(2x) sq - 6x -6x -x sq = 9-9
xsq - 12x =0
x(x-12) = 0
x-12=0/x
x-12=0
x=12

so now
BC = x = 12
AB=12-3 = 9
AC = x +3 = 12+3 = 15

Answer 2

That is the correct answer of this question