Math, asked by coolkhanamit1978, 8 months ago

In a right angled triangle ABC, angleA = 90° and AD I BC. Prove that AD2 = BD x CD.

Answers

Answered by vrushant

0

Answer:

adding eq (1) and (2)

Step-by-step explanation:

BD²+DC²+2AD²=AC²+AB²

From (1) we replace rhs from above equation to get :

BD²+DC²+2AD²=Bc²

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