Question

In a right angled triangle ABC, if AB=8cm, AC=6 cm then find sin C and tanB​

Answer 1

Answer:

Sin C = 4/5

Tan B = 3/4

Step-by-step explanation:

Assume a right triangle ABC right-angled at A

So applying Pythagoras theorem in Δ ABC , we get

(AB)² + (AC)² = (BC)²

(8)² + (6)² = (BC)²

64 + 36 = (BC)²

100 = (BC)²

BC = 10

Sin C = AB/BC = 8/10 = 4/5

Tan B = AC/AB = 6/8 = 3/4

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