Question

in a right angled triangle ABC, right angeled at C . in which AB =13cm ,BC=5cm . then prove that sin²A + cos ²B=50/109​

Answer 1

Answer:

in a right angle triangle ABC,

angle ACB=90°

AB= 13 cm

BC=5cm

so, AC=√(AB^2-BC^2) cm

=√(13^2-5^2) cm

=√(169-25) cm

=√144 cm

=12 cm

sin^2A+cos^2B

=(BC/AB)^2+(BC/AB)^2

=25/169+25/169

=50/169 (proved)