Math, asked by PROlearnerO1O1, 4 months ago

In a right angled triangle ABC right angle at C .P and Q are the points on the side CA and CB respectively, which divides these sides in the ratio 2:1. prove that...Plz fast...
(i) \: 9bp^{2}  = 9bc^{2} + ac^{2}\\(ii) \: 9(aq{2}  + bp^{2} ) = 13ab^{2}

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Answered by Anonymous
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