Question

In a right-angled triangle ABC, right-angled at A, if BC = 41 cm, CA = 40 cm, find sinB and tan C

Answer 1

Answer:

in triangle ABC

BC=41 ,CA=40

by Pythagoras theorem

AC^2=BC^2+AB^2

41^2=40^2+AB^2

1651=1600+AB^2

1651-1600=ab^2

51=AB^2

AB=root 51

sin=p/h=40/41

tan =p/b=root51/40

Answer 2

Answer:

Step-by-step explanation:

in triangle ABC

BC=41 ,CA=40

by Pythagoras theorem

AC^2=BC^2+AB^2

41^2=40^2+AB^2

1651=1600+AB^2

1651-1600=ab^2

51=AB^2

AB=root 51

sin=p/h=40/41

tan =p/b=root51/40