In a right-angled triangle ABC, right-angled at A, if BC = 41 cm, CA = 40 cm, find sinB and tan C
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Answered by
1
Answer:
in triangle ABC
BC=41 ,CA=40
by Pythagoras theorem
AC^2=BC^2+AB^2
41^2=40^2+AB^2
1651=1600+AB^2
1651-1600=ab^2
51=AB^2
AB=root 51
sin=p/h=40/41
tan =p/b=root51/40
Answered by
1
Answer:
Step-by-step explanation:
in triangle ABC
BC=41 ,CA=40
by Pythagoras theorem
AC^2=BC^2+AB^2
41^2=40^2+AB^2
1651=1600+AB^2
1651-1600=ab^2
51=AB^2
AB=root 51
sin=p/h=40/41
tan =p/b=root51/40
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