Question

In a right-angled triangle ABC, right angled at B, AB = 6 cm , BC= 8 cm , then AC = *

Answer 1

Answer:

AC= 10cm

Step-by-step explanation:

AB =6 cm  

BC = 8 cm

(AC)^2 = (AB)^2 + (BC)^2( hypotenuse)

(AC)^2 = (8)^2 + (6)^2

(AC)^2 = 64+36

(AC)^2 = 100

AC = 10 cm

Hope it helps u..

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Answer 2

Step-by-step explanation:

$\large \rm \red{ {\underline {\underline{Given:-}}}}$

• A right angled triangle is right angled at B

• AB = 6cm

• BC = 8cm

$\large \rm \blue{ {\underline {\underline{To\:Find:-}}}}$

• The Value of the line AC

$\large \rm \green{ {\underline {\underline{Given:-}}}}$

$\boxed{ \rm \pink{ {Hypotenuse}^{2} = {Base}^{2} + {Height}^{2} }}$

• Here:-

• Hypotenuse = AC

• Base = BC

• Height = AB

Substituting the values:-

${ \rm\rightarrow { {AC}^{2} = {8}^{2} + {6}^{2} }}$

${ \rm \rightarrow { {AC}^{2} = 64+ 36 }}$

${ \rm \rightarrow { {AC}^{2} = 100 }}$

${ \rm \rightarrow { AC = \sqrt{100} }}$

${ \rm \rightarrow { AC = 10 }}$

$\boxed{{ \rm \purple{\rightarrow { AC = 10cm }}}}$