In a right-angled triangle ABC, right angled at B, AB =
![\frac{x}{2} \frac{x}{2}](https://tex.z-dn.net/?f=+%5Cfrac%7Bx%7D%7B2%7D+)
BC = x + 2 and AC = x + 3. The
value of x is:
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In a right angled triangle ABC, AB=x/2,BC=x+2 and CA=x+3,then x is equal to what in length
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