Question

• In a right-angled triangle ABC, right angled at B, AB =x/2
BC = x + 2 and AC = x + 3. Find
value of x​

Answer 1

Step-by-step explanation:

AB^2+BC^2=AC^2

x^2/4+(x+2)^2=(x+3)^2

x^2/4+x^2+4x+4=x^2+6x+9

x^2/4+4x+4=6x+9

x^2/4-2x-5=0

x^2-8x-20=0

(x-10)(x+2)=0

x=10

Answer 2

Answer:

In a right-angled ∆ ABC, right angled at B

AB =x/2

BC = x + 2

AC = x + 3.

AB + BC + AC = 180°

x/2 + x+2 + x+3 = 180°

x/2 + 2x + 5 = 180°

5x + 5 = 180°

5x = 180 - 5

x = 175/5 = 35°

x = 35°

Hope it helps!!

Please do mark my answer as the brainliest!!!