Question

In a right angled triangle ABC right angled at B , BC =3 and AC=6 determine BCA and BAC​

Answer 1

Answer:

60 degrees

Step-by-step explanation:

Using the trigonometric principles ,

sin (ABC) =

AB/AC = 3/6 = 1/2

Thus, angle ACB = 30 degrees

angle BAC = 90 - angle ACB

90 - 30 = 60 degrees

HOPE YOU FIND IT EASY TO UNDERSTAND !