Question

In a right angled triangle ABC right angled at B given 15 cosA-8sín A=0 then
sin A + COS A
2 cos A-sinA​

Answer 1

Answer:

Given that

tanA=  

1

3

​  

 

​  

 

AC=  

(  

3

​  

)  

2

+1  

2

 

​  

 

=  

3+1

​  

 

=  

4

​  

 

=2

​  

 

now

(i)sinAcosC+cosAsinC

=  

2

3

​  

 

​  

×  

2

3

​  

 

​  

+  

2

1

​  

×  

2

1

​  

 

=  

4

3

​  

+  

4

1

​  

=  

4

4

​  

=1

​  

 

and  

(ii)cosAcosC−sinAsinC

=  

2

1

​  

×  

2

3

​  

 

​  

−  

2

1

​  

×  

2

3

​  

 

​  

 

=  

4

3

​  

 

​  

−  

4

3

​  

 

​  

 

=0

​  

 

Step-by-step explanation: