In a right angled triangle ABC ,right angled at C,if tan A=1,then justify that 2 Sin A×Cos A=1
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tan A=P/B =1 so P=1 and B=1 so H = √2
by H²=P²+ B² now 2sin A×cos A = 2 × 1/√2 x 1/√2 = 2/2 =1
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