Question

In a right angled triangle ABC with angle A equal to 90°, find angle B and C so that sin(B) =cos (B) A (3)​

Answer 1

Answer:

Given in △ ABC, ∠B=90⁰

This given A+C=180⁰−90⁰=90⁰ ..(1).

Now,

sinA.cosC+cosA.sinC

=sin(A+C)

=sin(90⁰)

=1

Hope this helps you

:)