Question

in a right angled triangle ABC with angle B=90°,angleA=60° and AC=15cm.find the remaining sides of the triangle ABC​

Answer 1

Answer:

ABC is right angled at C, ∠B=60

∘∠C=90

∘We know that,In triangle ABC, ∠A+∠B+∠C=180

∘60

∘ +∠A+90

∘ =180

∘∆A=30

∘We have,sinA= AB,CB sin 30

∘ = 15Cb 21 ×15=CB

CB=7.5 units

From Pythagoras theorem,

AB 2 =AC 2+BC

2152 =AC 2 +( 215 ) 2

AC 2 =225−( 4225 )

AC 2 =225( 43 )

AC= 2153 units