In a right angled triangle base BC=15cm and sinB=4/5 then what is the length of hypotenuse AB
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There fore the length of hypotunse AB is 15cm
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In right triangle ABC tan C=4/3 . or AB/BC= 4/3
AB= 4.BC/3
In right angled triangle ABC :-
(AB)^2+(BC)^2=(AC)^2 , on putting AB=4.BC/3 and AC=15cm.
(4BC/3)^2+(BC)^2=(15)^2
16.(BC^2)/9 +BC^2 =225
25.(BC^2)/9=225
BC^2=225×9/25= 81
BC= 9 cms
But AB=4.BC/3=4×9/3 =4×3 =12 cms
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